Discrete Expected Value
. The possible outcomes (X) are {1, 2, 3, 4, 5, 6}, and each outcome has a probability of 1/6. The expected value is: E(X) = (1)(1/6) + (2)(1/6) + (3)(1/6) + (4)(1/6) + (5)(1/6) + (6)(1/6) = 3.5 This means that if you were to roll the die many times, the average value o