Mechanics Of Materials Problems And Solutions
rac{b h^3}{12} = \frac{0.02 \times (0.04)^3}{12} = 1.07 \times 10^{-8}\, \text{m}^4 \] - Distance to outer fiber \(c = h/2 = 0.02\, \text{m}\), \[ \sigma_{bending} = \frac{M c}{I} = \frac{10,000\, \text{Nm} \times 0.02\, \text{m}}{1.07 \times 10^{-8}} \approx 18.7\, \text{